In the given figure,the incircle of triangle ABC touches the sides BC,CA and AB at P,Q and R respectively Prove that (AR+BP+CQ)=(AQ+BR+CP).

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srry this is the complete question:
In the given figure,theincircleof triangle ABC touches the sides BC,CA and AB at P,Q and R respectively Prove that (AR+BP+CQ)=(AQ+BR+CP)=1/2 ABC
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got the ans . thx a lot
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