In the given trapezium , if AP = BP, QP = QC and QD= 2cm then find the area of (ABCD) Share with your friends Share 2 Dhruvil .i. Patel answered this area (abcd) =area(abp +bqc+apd) = 8+10.5+10 =28.5 -1 View Full Answer Trisha Krishnan answered this Please find this answer 3 Neha Thomas answered this area (abcd) =area(abp +bqc+apd) = 8+10.5+10 =28.5 0 Neha Thomas answered this area (abcd) =area(abp +bqc+apd) = 8+10.5+10 =28.5 1
