In the given trapezium , if AP = BP, QP = QC and QD= 2cm then find the area of (ABCD)

area (abcd) =area(abp +bqc+apd)
                   = 8+10.5+10
                   =28.5
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  • 2
area (abcd) =area(abp +bqc+apd)
                   = 8+10.5+10
                   =28.5
  • 1
area (abcd) =area(abp +bqc+apd)
                   = 8+10.5+10
                   =28.5 
  • 1
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