In the next Republic day parade the commander of an army contingent  consisting of 624 membars wants to march his contingent behind an army band of 32 members such that the two groups march in same number of coloums . What is the maximum numberof coloumns in which the two groups can march? what vaue is depicted from this action?

Here we will find the HCF of 624 and 32.Prime factorisation of 624 and 32 are 624 = 2×2×2×5332 = 2×2×2× 2×2 HCF = 2×2×2 = 8so, maximum number of columns = 8

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