In this i am getting opposite values of tan and cot. I am getting 4cotx & 9 tanx and also how are both of them equal to 36 ? -
19:23 Let AB be the tower. C and D be the two points with distance 4 m and 9 m from the base respectively. A/q, In right
AABC, tan x = AB/BC tan x = AB/4 AB = 4 tan x
(i) also, In right AABD, tan (900-x) = AB/BD cot x = AB/9 AB = 9 cot x
(ii) Multiplying eqn (i) and (ii) AB2 = 9 cot xx 4 tan x AB2 = 36
Height cannot be negative. Therefore, the height of the tower is 6 m. Hen Proved.

Dear student
We request you to mention the statement of the question along with the solution highlighting your doubt so that we can provide you with meaningful help.Looking forward to hear from you again .
Regards

  • -1
What are you looking for?