In triangle ABC ,AB=20 cm BC =21 cm. If perimeter of triangle ABC is 70 cm, find its area.

In ABC, we have,AB = 20 cm; BC = 21 cm and AC = ?Perimeter of ABC = 70 cmNow, AB + BC + CA = 7020 + 21 + CA = 70CA = 29 cmSo, we have, a = 20 cm; b = 21 cm; c = 29 cmNow, semiperimeter, s = 702 = 35 cmNow, area of ABC = ss-as-bs-c=3535 - 2035 - 2135 - 29=35 × 15 × 14 × 6=210 cm2

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Given:we have ?ABC, AB=20, BC=21 Peri.=70
AB+BC+CA=Perimeter
20+21+CA=70
CA=70-41=29
semi peri.=70/2=35

by using Heron's formula area= 210.sq.cm
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double of perimeter

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