In triangle ABC,angleA=50degree and BC is produced to a point D. The bisectors of angleABC and angleACD meet at E. Find angle E
In ∆ABC, BE is the interior angle bisector of ∠B and CE is the exterior angle bisector of ∠C.
Now In ΔABC
∠A + ∠B + ∠C = 180°
⇒ ∠A = 180° – x – y .... (1)
Now in ΔBCE,
ÐB = ,
ÐC = y +
And ÐB + ÐC + ÐE = 180°
From (1) and (2)
Þ ÐE = 25°