- in triangle ABC.D id the mid-point of AB &P is any point on BC.if CQ is parallel to PD meets AB in Q,then prove that :-

ar(BPQ)=1/2ar(ABC

** Given that**: ABC is a triangle and D is the mid-point of AB and P is a point on BC such that PD||CQ.

** To Prove**:

** Construction**: join C to D

__proof:__

Since D is mid-point on AB, so CD is a median of the

Thus,

Now and are on the same base PD and between the same parallels PD and CQ.

So,

From equation (1), we get,

So,

Hence,

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