- in triangle ABC.D id the mid-point of AB &P is any point on BC.if CQ is parallel to PD meets AB in Q,then prove that :-
ar(BPQ)=1/2ar(ABC
Given that: ABC is a triangle and D is the mid-point of AB and P is a point on BC such that PD||CQ.
To Prove:
Construction: join C to D
proof:
Since D is mid-point on AB, so CD is a median of the
Thus,
Now and are on the same base PD and between the same parallels PD and CQ.
So,
From equation (1), we get,
So,
Hence,