In triangle ABC, if L and M are the points on AB & AC respectively, such that LM is parallel to BC. If BM & CL intersect at O, prove that area of traingle LOB = area of triangle MOC.
Hi!

ΔBLC and ΔCMB are on same base BC and have the same height as LM||BC.
Therefore ar(ΔBLC) = ar (ΔCMB)
ar(ΔLOB) + ar(ΔBOC) = ar(ΔMOC) + ar (ΔBOC)
ar(ΔLOB) = ar(ΔMOC)
Cheers!