# In triangle ABC, if L and M are the points on AB & AC respectively, such that LM is parallel to BC. If BM & CL intersect at O, prove that area of traingle LOB = area of triangle MOC.

Hi!

We have LM||BC

ΔBLC and ΔCMB are on same base BC and have the same height as LM||BC.

Therefore ar(ΔBLC) = ar (ΔCMB)

$⇒$ ar(ΔLOB) + ar(ΔBOC) = ar(ΔMOC) + ar (ΔBOC)

$⇒$  ar(ΔLOB) = ar(ΔMOC)

Cheers!

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Thank you sir..!

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