in triangle DEF,M and N are midpoints of sides EF and DE respectively.IF ar(EMN)=4 sq.cm,find ar(DEF) Share with your friends Share 2 Anuradha Sharma answered this In ∆DEF, as M and N are the mid points of the sides EF, ED so using mid point theorem, MN|| DF and MN = 12DFSince MN∥FD and EF is a transversal, then∠EMN = ∠EFD Correponding anglesSince MN∥FD and ED is a transversal, then∠ENM= ∠EDF Correponding anglesIn ∆ENM and ∆EDF,∠EMN = ∠EFD Correponding angles∠ENM= ∠EDF Correponding angles⇒∆ENM ~ ∆EDF AA similarityWe know that ratio of areas of 2 similar ∆'s is equal to the square of the ratio of their corresponding sides.So, ar∆ENMar∆EDF = NMDF2 = DF2DF2 = 14⇒4ar∆EDF = 14⇒ar∆EDF = 16 cm2 6 View Full Answer