in two digit number, the digit at the units place is double the the digit in the tens place. the number exceeds the the sum of its digit by 18 .find the number.
Let the digit at tens place be x
Units Place = 2x
Original number = 10(x) + 2x = 12x
Interchanged number = 10(2x) + x = 21x
21x - 12x = 18
9x = 18
x = 2
Original number = 10*2 + 2*2 = 24