in two digit number, the digit at the units place is double the the digit in the tens place. the number exceeds the the sum of its digit by 18 .find the number.

Let the digit at tens place be x

Units  Place = 2x

Original number = 10(x) + 2x = 12x

Interchanged number = 10(2x) + x = 21x

21x - 12x = 18

9x = 18

x = 2

Original number = 10*2 + 2*2 = 24

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ans.24

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 ans. 24

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