Is it possible to construct a rhombus ABCD where AC=6cm and BD=7cm, justify your answer

1.Draw BD=6cm

2.Draw a perpendicular bisector PQ of BD to bisect BD at O

3.With O as the center and radius equal to 3cm =(1/2 AC),draw arcs to intersect POQ at C and A,on opposite side of BD 

4.Join AB,BC,CD and DA 

Thus ABCD is the required rhombus.

Rough figure: