It is given that 106062 is divisible by 33. Which two numbers nearest 106062 are each divisible by 33. i am really confused with this question.... could any one help me out. Share with your friends Share 3 Tanveer Sofi answered this Since 33 is the product of two prime numbers 3 and 11. Thus a number willbe divisible by 33 if it is both divisible by 3 as well as 11.A number is divisible by 3, if the sum formed by adding its digits is divisible by 3.A number is divisible by 11, if the difference of the sum of digits at odd places and the sum of its digits at even places, is either 0 or divisible by 11, then clearly the number is divisible by 11. Now, it is given that the number 106062 is divisible by 33. The two numbers nearest to 106062 which are also divisible by 33 are106062-33=106029 and 106062+33=106095. 2 View Full Answer
