k is an integer such that,
  9 < k^2 < 99
If MAXIMUM value of k = p and
    A MINIMUM value of k = q
  What is ( p - q ) ?
Hint : ( k can take both positive and negative values )
 
a) 5   b) 8  c) 13  d) 18




 

Hi, 9<k2<99so here k can be ±4,±5,±6,±7,±8,±9because taking -4, 16 lies between 9 and 99 and taking value 9,  lies between 9 and 99so here maximum value of k = 9 = p and minimum value of k = - 9 = q so p-q = 9--9= 18

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kmax=9=p  and kmin=-9 =q
p-q = 9--9 = 9+9 = 18
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the above answer is wrong the correct answer is 9-4=5
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