k is an integer such that, 9 < k^2 < 99 If MAXIMUM value of k = p and A MINIMUM value of k = q What is ( p - q ) ? Hint : ( k can take both positive and negative values ) a) 5 b) 8 c) 13 d) 18 Share with your friends Share 0 Brijendra Pal answered this Hi, 9<k2<99so here k can be ±4,±5,±6,±7,±8,±9because taking -4, 16 lies between 9 and 99 and taking value 9, lies between 9 and 99so here maximum value of k = 9 = p and minimum value of k = - 9 = q so p-q = 9--9= 18 1 View Full Answer Aravind K Thilakan answered this kmax=9=p and kmin=-9 =q p-q = 9--9 = 9+9 = 18 0 Satyam Sinha answered this the above answer is wrong the correct answer is 9-4=5 0