Kindly show this with Full explaination with each step. Last time what experts gave I can't understand anything in it.
Thanking you in advance.
Dear student,
Given, 2-digit number is 32 less than the square of the product of its digits.
Now, let us consider some of the square terms 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121.
We need not consider above 121, because after subtracting 32 the result should be a two digit number.
Now, we can also discard 1, 4, 9, 16, 25, 36. As by subtracting 32 from these numbers we don't get a two digit number.
Now remaining squares are 49, 64, 81, 100, 121
After subtracting 32 above terms becomes as 17, 32, 49, 68, 89
Now product of digits is 7, 6, 36, 48, 72
After squaring these terms we should get the previous square terms.
7² = 49, 6² 64, 36² 81, 48² 100, 72² 121
So, the only number satisfying our conditions is 17.
Hence, sum of digits of the two digit number is 1 + 7 = 8
Regards.
Given, 2-digit number is 32 less than the square of the product of its digits.
Now, let us consider some of the square terms 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121.
We need not consider above 121, because after subtracting 32 the result should be a two digit number.
Now, we can also discard 1, 4, 9, 16, 25, 36. As by subtracting 32 from these numbers we don't get a two digit number.
Now remaining squares are 49, 64, 81, 100, 121
After subtracting 32 above terms becomes as 17, 32, 49, 68, 89
Now product of digits is 7, 6, 36, 48, 72
After squaring these terms we should get the previous square terms.
7² = 49, 6² 64, 36² 81, 48² 100, 72² 121
So, the only number satisfying our conditions is 17.
Hence, sum of digits of the two digit number is 1 + 7 = 8
Regards.