# Let BP and BQ be the magnetic field produced by the wire P and Q which are placed symmetrically in a  rectangular loop ABCD as shown in figure. Current in wire P is I directed inward and in Q is 21 directed outwards. If $\underset{A}{\overset{B}{\int }}{\stackrel{\to }{B}}_{Q}·\stackrel{\to }{d\mathcal{l}}=2{µ}_{0}$ tesla meter, $\underset{D}{\overset{A}{\int }}{\stackrel{\to }{B}}_{P}·\stackrel{\to }{d\mathcal{l}}=-2{µ}_{0}$ tesla meter & $\underset{A}{\overset{B}{\int }}{\stackrel{\to }{B}}_{P}·\stackrel{\to }{d\mathcal{l}}=-{µ}_{0}$ tesla meter the value of I will be: (A) 8 A                    (B) 4 A                  (C) 5 A                    (D) 6 A

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