Let S be the focus of the parabola y2 = 8x and let PQ be the common chord of the circle

x2 + y2 – 2x – 4y = 0 and the given parabola. The area of the triangle PQS is.

The given parabola  is of the form where, 4a=8, a=2

The coordinates of focus are (a, 0) i.e. (2, 0)

Let any point onLet any point  be

Since, this point lies on


For t=1, point Q = (2, 4)

For t = 0, point P = (0, 0)

And the co-ordinates of focus are S= (2, 0).

So, Area of triangle PQS,

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