let the escape velocity of a body kept at a surface of a planet is u. if it is projected at a speed of 200% more than the escape speed, then it's speed in interstellar space will be

Refer to the attached image

Let v be the speed with which the body was thrown and u be the minimum escape speed. Therefore, v = ku u + 2u = ku 3u = ku k = 3 And then, [(3×3) - 1]^1/2 × u Which is equal to = 2√2 u

I don't know

do yourself.

Let v be the speed with which the body was thrown and u be the minimum escape speed. Therefore, v = ku u + 2u = ku 3u = ku k = 3 And then, [(3?3) - 1]^1/2 ? u Which is equal to = 2?2 u

Here is the formula:-