Limit x tends to 0 x2-5x+6/x2+2x-8 Share with your friends Share 0 Varun.Rawat answered this I assume the question should be evaluate limx→2 x2-5x+6x2+2x-8 instead of limx→0 x2-5x+6x2+2x-8 limx→2 x2-5x+6x2+2x-8=limx→2 x2-3x-2x+6x2+4x-2x-8=limx→2xx-3-2x-3xx+4 - 2x+4=limx→2x-2x-3x-2x+4=limx→2x-3x+4=2-32+4=-16 0 View Full Answer
