limxtend to 3 x^3-27/root x^2+7-4

the given limit is 
limx3x3-27x2+7-4  i.e. 00 formso we can apply L'Hospital rule:limx3ddx(x3-27)ddx(x2+7-4)=limx33x212x2+7.2x=limx3[3.x2+7]=3*32+7=3*9+7=3*16=3*4=12

hope this helps you

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