Locate the centre of mass of arrangement shown in figure. The three rods are identical in mass and length:-

a) (L/2,L/2)
b) (L/3,0)
c) (L/3,L/2)
d) (0,L/3)

Hi,

Please find below the solution to the asked query:

The system has three rodsFor the first rod(Along X axis)the center of mass of this rod is at (L2,0)For the second rod(Along Y axis)the center of mass of this rod is at (0.L2)while for the third rodthe center of mass  is at (L2,L)let us assume the mass of each rod to be m.thus the center of mass of the system is at :Xcom = m1x1+m2x2+m3x3m1+m2+m3so we have m1 = m2 =m3 = mso Xcom= mL2+0+mL23m = L3similarly Ycom = m1y1+m2y2+m3y3m1+m2+m3so we have m1 = m2 =m3 = mYcom= 0+mL2+mL3m = L2so co ordinates of COM = L3,L2

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