log5+log(x+10)-1= log(21x-20)-log(2x-1) solve this

log 5+log x+10-1=log 21x-20-log2x-1log 5+log x+10-log10=log 21x-20-log2x-1log 5+log x+10-log 10=log 21x-20-log2x-1Use log m +log n=logmnlog 5x+10-log 10=log 21x-20-log2x-1Use log m -log n=logmnlog 5x+1010=log 21x-202x-15x+1010=21x-202x-1x+102=21x-202x-1x+102x-1=42x-402x2-x+20x-10=42x-402x2+19x-10=42x-402x2-23x+30=02x2-23x+30=02x2-20x-3x+30=02xx-10-3x-10=0x-102x-3=0Either x-10=0 or 2x-3=0x=10 or x=32

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