Maximum no. of hydrogen atoms are in-

1)16 gof CH4

2)31.2 g of C6H4

3)34.2g of C12H22O11

4)36 g of C6H12O6

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To solve, use the formula: mole = mass/molar mass to determine the moles of the different molecules

Number of atoms of the hydrogen is given in the molecular formula

- 16g of CH
_{4}Molar mass = 16g/mol

Moles of CH

Number of molecules of CH

Each molecule of CH

(Avogadro number does not affect the result, so it is not included as a number in the calculation)._{4}= 16/16 = 1molNumber of molecules of CH

_{4}= moles $\times $ Avogadro number (N_{A}) = 1 N_{A}Each molecule of CH

_{4}contains 4 hydrogen atoms (subscript below H is the number of atoms)**So, number of hydrogen atoms in CH**$\times $_{4}are = 4**1**$\times $**N**_{A}= 4N_{A}We repeat the same for the rest of the molecules.

- 31.2g of C
_{6}H_{4}molar mass = 76g/mol

Moles = 31.2/76 = 0.41mol

**Number of H atoms = 4**$\times $**0.41**$\times $**N**_{A}= 1.6 N_{A}- 34.2g of C
_{12}H_{22}O_{11}_{ }molar mass= 342g/mol

Moles = 34.2/342 = 0.1mol

4. 36g of C**Number of H atoms = 22**$\times $**0.1**$\times $**N**_{A}= 2.2 N_{A}_{6}H

_{12}O

_{6}molar mass= 180g/mol

Moles = 36/180 = 0.2mol

Maximum number of Hydrogen atoms are in 16g of CH**Number of H atoms = 12 X 0.2 X N**_{A}= 2.4 N_{A}_{4}

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