Maximum no. of hydrogen atoms are in-

1)16 gof CH4

2)31.2 g of C6H4

3)34.2g of C12H22O11

4)36 g of C6H12O6

SIR/MADAM,CAN U PLEASE GIVE THE EXPLANATION FOR THIS SUM AND ALSO NOTE ,ON WHICH CONCEPT IS IT BASED ON, IT'S FORMULA...

The number of atoms of an element in a molecule depends on the moles of the substance present in the given mass and number of atom of the element present per molecule.
 To solve, use the formula:  mole = mass/molar mass to determine the moles of the different molecules
Number of atoms of the hydrogen is given in the molecular formula
  1. 16g of CH4   Molar mass = 16g/mol
Moles of CH4 = 16/16 = 1mol
Number of molecules of CH4  =  moles × Avogadro number (NA) = 1 NA
Each molecule of CH4 contains 4 hydrogen atoms (subscript below H is the number of atoms)
So, number of hydrogen atoms in CH4 are = 4 × 1 × NA = 4NA
(Avogadro number does not affect the result, so it is not included as a number in the calculation).
We repeat the same for the rest of the molecules.
  1. 31.2g of C6H4  molar mass = 76g/mol
Moles = 31.2/76 = 0.41mol
Number of H atoms = 4 × 0.41 × NA = 1.6 NA
 
  1. 34.2g of C12H22O11  molar mass= 342g/mol
Moles = 34.2/342 = 0.1mol
Number of H atoms = 22 × 0.1 × NA= 2.2 NA
 
   ‚Äč4.  36g of C6H12O6  molar mass= 180g/mol
Moles = 36/180 = 0.2mol
Number of H atoms = 12 X 0.2 X NA = 2.4 NA
 
Maximum number of Hydrogen atoms are in 16g of CH4

  • 14
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