[NiCl4]2- .

explain the bonding in coordination compounds ?

show the hybridisation in [NiCl4]2- .

and explain each nad every step in hybridisation

Dear student!

The compound [NiCl4]2- , has sp3 hybridization which is determined as:

At step 1: we find the metal cation and as, x + (-4) = -2  or x = +2, So, metal ion is Ni+2 ion , whose configuration is 3d8 

Step2 : Further, Cl, forms high spin complex , it could not pair up the unpaired electrons of 3d-orbital and so the four electrons pair donated by Cl-atoms are arranged in 4 sp3 hybridized orbitals.

The detailed mechanism is given as below:

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