No links please: (i) Let x be a random variable which takes the value x 1 , x 2 , x 3 , x 4 , p ( x = x 4 ) = 0 . 5 , p x > x 2 = 0 . 8 a n d i f p x = x 1 , p ( x = x 3 ) are A.P. Find the probability distribution. Share with your friends Share 0 Neha Sethi answered this Dear student Given, px=x4=0.5=12Also, p(x>x2)=0.8⇒px=x3+px=x4=0.8⇒px=x3+0.5=0.8⇒px=x3=0.3=310 ...(1)Also,px=x1+px=x2+px=x3+px=x4=1⇒px=x1+px=x2+0.8=1 ∵px=x3+px=x4=0.8⇒px=x1+px=x2=0.2⇒px=x1=0.2-px=x2 ...(2)Also, px=x1,px=x2,px=x3 are in A.PSo, 2px=x2=px=x1+px=x3⇒2px=x2=0.2-px=x2+0.3 [using 1 and 2]⇒3px=x2=0.5⇒px=x2=16Put the value of px=x2 in (2), we getpx=x1=0.2-16⇒px=x1=130 Probability distribution is xi x1 x2 x3 x4 p(xi) 130 16 310 12 Regards 0 View Full Answer Divyanshi Agarwal answered this Please find this answer 0