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Q. Eight dice are thrown 6561 times. How many times can one expect at least tow dice to show a 2 or 3 or 4 or 5 ?


 

Dear student
  Probability of getting a 2 or 3 or 4 or 5=46=23Hence p=23 and q=1-p=1-23=13and n=6 and r=2Therefore, probability of getting 2 or 3 or 4 or 5 in atleast 2 dice is 1-P(X=0)+P(X=1)=1-6C0236-0130+6C1236-1131    As P(X=r)=6Cr236-r13r=1-236+623513=1-23523+2=1-32243×83=1-256729=473729
Regards

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