No. Of waves of orange light emitted by krypton in 1m is __________???
How to find this ???
Dear Student,
the length is 1 meter in total in which the orange light will be visible.
Wavelength of Kr 86 is known to be 605 nm (orange in visible region)
So number of wavelengths in 1 meter = 1/605 * 10^-9.
Number of Wavelengths = 1652892.562.
The number of wavelength will be 1652892.562
Regards
the length is 1 meter in total in which the orange light will be visible.
Wavelength of Kr 86 is known to be 605 nm (orange in visible region)
So number of wavelengths in 1 meter = 1/605 * 10^-9.
Number of Wavelengths = 1652892.562.
The number of wavelength will be 1652892.562
Regards