Number of ordered pairs of integers (n,m) for which n^2-m^2=14 is. (A)0 (B)1 (C)2 (4) Share with your friends Share 0 Neha Sethi answered this Dear student We haven2-m2=14⇒n-mn+m=14Now we know that ,14=1×1414=-1×-1414=2×714=-2×-7Case 1: When n-m=1and n+m=14On adding the above equations, we get2n=15⇒n=152But n here is not an integer . So this case is not possible.Case 2: when n-m=-14 and n+m=-1On adding the above equations, we get2n=-15⇒n=-152But n here is not an integer . So this case is not possible.Case 3: When n-m=2and n+m=7On adding the above equations, we get2n=9⇒n=92But n here is not an integer . So this case is not possible.Case 4:When n-m=-7and n+m=-2On adding the above equations, we get2n=-9⇒n=-92But n here is not an integer . So this case is not possible.So, there is no possible ordered pair.Hence correct option is A. Regards -1 View Full Answer