numbers 1-20 were writtenon chits of paper and dropped in box what is the probability of

a-choosing muliples of 10

b-choosing an even number

c-choosing an odd prime number

d-choosing a factor of 6

The sample space is given by:S = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20Thus n S = 20a.    Let E1 = event of choosing a multiple of 10 = 10, 20         Then, n E1 = 2         Therefore, p E1 = n E1n S = 220 = 110b.     Let E2 = event of choosing an even number = 2, 4, 6, 8, 10, 12, 14, 16, 18, 20           Then,  n E2 = 10           Therefore, p E2 = n E2n S = 1020 = 12 


c.    Let E3 = event of choosing an odd prime number = 3, 5, 7, 11, 13, 17, 19          Then, n E3 = 7          Therefore, p E3 = n E3n S = 720d.     Let E4 = event of choosing a factor of 6 = 1, 2, 3, 6           Then, n E4 = 4           Therefore, p E4 = n E4n S = 420 = 15

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1. total no.of outcomes= 20

favourable outcomes= 10,20=2

so probability= 2/20=1/10

2.total no.of outcomes=20

favourable outcomes= 2,4,6,8,10,12,14,16,18,20

=10

so probability= 10/20=1/2

3. total no.of outcomes=20

favourable outcomes= 3,5,7,11,13,17,19

=7

probability= 7/20

4. total no.of outcomes=20

favourable outcomes= 2,3

=2

probability= 2/20=1/10

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