O IS THE CENTRE OF THE CIRCLE. IF ANGLE AOB= 80 degree THEN FIND THE MEASURE OF ANGLE ADB AND ANGLE ACB.PLEASE PROVIDE THE DIAGRAM.

Dear student,
You have not provided the information about the points C and D, so I am taking point C in the major segment of circle and D in the minor segment of the circle.
Here is the solution.



We know that angle subtended by an arc at the centre is double the angle subtended by the same arc at any point on the circle.Consider the minor arc AB, that subtends AOB at the centre and ACB on the circle.Now, AOB = 2ACBACB = AOB2 = 80°2 = 40°Since ADBC, is a cyclic quadrilateral, thenADB + ACB = 180°   Opposite angles of cyclic quadrilateral are supplementaryADB + 40° = 180°ADB = 140°

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I can't draw the diagram.
But
If AB is a chord and O is the centre of the circle. Then angle AOB = 80
So, angle ACB= 40 and angle ADB=40 (angles subtended by the chord at the centre is double of the angle subtended by the same chord at any other point on the circle.)
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What are you looking for?