Obtain all the zeroes of the polynomial f(x)= 2x4-2x3-7x2+3x+6, if its two zeroes are√3/2 and - √3/2
Given:
f(x) = 2x4 –2x3 – 7x2 + 3x + 6
Now
So, f (x) = 2x4 – 2x3 – 7x2 + 3x + 6
= (2x2 – 3) (x2 – x – 2)
= (2x3 – 3) (x + 1) (x – 2)
Hence the other two zeroes of f (x ) are – 1 and 2.