Obtain all the zeroes of the polynomial f(x)= 2x4-2x3-7x2+3x+6, if its two zeroes are√3/2 and - √3/2

Given:

f(x) = 2x4 –2x3 – 7x2 + 3x + 6

Now

So, f (x) = 2x4 – 2x3 – 7x2 + 3x + 6

= (2x2 – 3) (x2x – 2)

= (2x3 – 3) (x + 1) (x – 2)

Hence the other two zeroes of f (x ) are – 1 and 2.

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