obtain the approximate value of the radius of
1.a nucleus of 4
2He.
2.a nucleus of 238
92 U
3.what is the ratio of these raddi..

Given,Mass no of He, A=4Empirical constant, R0=1.2×10-15 maRadius R is given byR=R0A13R=1.2×10-15×413R=1.2×10-15×1.587=1.905×10-15 mbMass no of uranium, A=238Now, R'=R0A13R'=1.2×10-15×23813=1.2×10-15×6.197R'=7.437×10-15 mcRR'=1.9057.437=0.256

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