obtain the approximate value of the radius of 1.a nucleus of 4 2He. 2.a nucleus of 238 92 U 3.what is the ratio of these raddi.. Share with your friends Share 5 Govind answered this Given,Mass no of He, A=4Empirical constant, R0=1.2×10-15 maRadius R is given byR=R0A13⇒R=1.2×10-15×413⇒R=1.2×10-15×1.587=1.905×10-15 mbMass no of uranium, A=238Now, R'=R0A13⇒R'=1.2×10-15×23813=1.2×10-15×6.197⇒R'=7.437×10-15 mcRR'=1.9057.437=0.256 2 View Full Answer