on putting x=4,y=-5 in the equation 3x-2y-2k=0 then the value of k is wat

Given : 3x - 2y - 2k = 0

putting x = 4, y = -5, we get,

3 × 4 - 2 × (-5) - 2k = 0

⇒ 12 + 10 - 2k = 0

⇒ 22 - 2k = 0

⇒ 2k = 22

k = 22/2 = 11

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3(4)-2(5)-2k=0

12-10=2k

2=2k

k=2/2

k=1

easy:)

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 sorry lucia thats not there in the options 

the options are

(a)5

(b)2

(c)11 and (d)-11

-11()

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oh................. mam i think the question must be wrong

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1. On putting x = 4, y = –5 in the equation

3x – 2y –2k = 0, the value of k is :

(a)5 (b)2 (c) 11 (d) –11

2. The equation of the line whose graph passes

through the origin, is :

(a) 2x + 3y = 1 (b) 2x + 3y = 0

(c) 2x + 3y = 6 (d) none of these

3. If x = –1, y = 4 is a solution of the equation

mx – y = – 6, then the value of m is :

(a)1 (b)2 (c) – 2 (d) 0

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