p.t any cyclic //gm is a rect. answer fast exams on monday

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Let ABCD be a cyclic parallelogram
Then,
∠A = ∠C (opposite ∠s of a llgram) .........(i)
and, ∠A + ∠C = 180⁰ (opposite angles of a cyclic quadrilateral are supplementary)
or, ∠A + ∠A = 180⁰    [From (i)]
​or, 2∠A = 180⁰
or, ∠A = 90⁰

​Therefore, ABCD is a rectangle, since one of its angles is 90⁰








 
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opposite angles of cyclic quadilateral is 180* so in a quadilateral ABCD angleA = angleC =  180 degree
2angleA = 180 degree
angle A = 180/2 = 90 degree
so wen angle A  is proved that its 90 degree we can say that ABCD is a rectangle (  angles of a rectangle is right angle which is 90 degree)
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