Physics electricity ch
Solution
Resistance between arm AC and CD are in series. So net resistance will be 6 ohm.
This resistance will be in parallel with resistance in arm AD
So
1/ RAD = 1/6 +1/6 = 1/3
RAD = 3 Ohm
Now again this 3 ohm is in series with resistance of arm DE. So net resistance is 3+3 = 6 Ohm
Similarly we can solve as shown in image. We will get 2 Ohm resistance between A and B
Resistance between arm AC and CD are in series. So net resistance will be 6 ohm.
This resistance will be in parallel with resistance in arm AD
So
1/ RAD = 1/6 +1/6 = 1/3
RAD = 3 Ohm
Now again this 3 ohm is in series with resistance of arm DE. So net resistance is 3+3 = 6 Ohm
Similarly we can solve as shown in image. We will get 2 Ohm resistance between A and B