Pl solve the fifteenth one

Dear Student.

Area of ABCD=Area of ABD+Area ofDCBSince area of equilateral triangle=34side2Hence Area of ABD=34×102=34×100=253 cm2In triangle BDC, by Pythagoras theorem:BC=BD2-CD2=100-64=36=6cmArea of triangle=12×base×height=12×6×8=24 cm2Hence area of ABCD=253+24=25×1.752+24=43.8+24=67.8 cm2

We hope that this answer solves your query.
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