Pl solve the fifteenth one Share with your friends Share 0 Yash Raj answered this Dear Student. Area of ABCD=Area of △ABD+Area of△DCBSince area of equilateral triangle=34side2Hence Area of △ABD=34×102=34×100=253 cm2In triangle BDC, by Pythagoras theorem:BC=BD2-CD2=100-64=36=6cmArea of triangle=12×base×height=12×6×8=24 cm2Hence area of ABCD=253+24=25×1.752+24=43.8+24=67.8 cm2 We hope that this answer solves your query. Regards. 0 View Full Answer