Solution 1 Initial velocity is 0 m/s as Vinay starts car so initially car is at rest Final v = 54 km/hr = 15 m/scorrect option (a)2) t = 1 min = 60su= 0 m/sv =15 m/sv = u + ata =v-ut = 1560 =0 25 m/s23)Distance covereds = ut +12at2 = 0+12×60×60×0 25 = 450 m Please post other parts in different thread to get rapid assitance from our experts

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1 . I n i t i a l v e l o c i t y i s 0 m / s a s V i n a y s t a r t s c a r s o i n i t i a l l y c a r i s a t r e s t . F i n a l v = 54 k m / h r = 15 m / s c o r r e c t o p t i o n (a) 2) t = 1 m i n = 60 s u = 0 m / s v = 15 m / s v = u + a t a = \frac{v - u}{t} = \frac{15}{60} = 0.25 m / s^{2} 3) D i s \tan c e c o v e r e d s = u t + \frac{1}{2} a t^{2} = 0 + \frac{1}{2} \times 60 \times 60 \times 0.25 = 450 m

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