please answer fast Q 24 Solve : (a 0) 2 logxa+ logaxa+3 loga2xa=0 - Maths - Binomial Theorem

Question

please answer fast
Q 24 Solve : (a > 0) 2   log x a +   log a x a + 3
  log a 2 x a = 0

Brijendra Pal · Accepted Answer

Hi, We know that logba= 1logabSo it can be written as 2logax+1logaax+3logaa2x= 0 2logax+1logaa+logax+3logaa2+logax= 0 2logax+11+logax+32+logax= 0 
<img alt="" src=
"https://s3mn%20mnimgs%20com/img/shared/content_ck_images/ck_5ae97708017a5%20png"
style="width: 265px; height: 165px;">

please answer fast. Q.24. Solve : (a > 0) 2 log x a + log a x a + 3 log a 2 x a = 0

please answer fast.
Q.24. Solve : (a > 0) $2 \log_{x} a + \log_{a x} a + 3 \log_{a 2 x} a = 0$