please answer fast.
Q.24. Solve : (a > 0) 2   log x a +   log a x a + 3   log a 2 x a = 0

Hi, We know that logba= 1logabSo it can be written as 2logax+1logaax+3logaa2x= 0 2logax+1logaa+logax+3logaa2+logax= 0 2logax+11+logax+32+logax= 0 

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