Solution For part a We know, E=hcλso EminEmax=λmaxλmin=43

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Solution

For part a.
We know,

E = \frac{h c}{λ} s o \frac{E_{m i n}}{E_{m a x}} = \frac{λ_{m a x}}{λ_{m i n}} = \frac{4}{3}

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