# Please answer my question?99

Equivalent circuit of the given circuit is shown which indicates that the three resistors are connected in parallel.

$\frac{1}{{R}_{PQ}}=\frac{1}{r}+\frac{1}{2r}+\frac{1}{2r}\phantom{\rule{0ex}{0ex}}or{R}_{PQ}=\frac{r}{2}$

option a is correct

Regards

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