#

please answer the 5 questions with explanation

4.

$AreaofRec\mathrm{tan}gle=length\times breadth\phantom{\rule{0ex}{0ex}}68\frac{3}{4}=12\frac{1}{2}\times breadth\phantom{\rule{0ex}{0ex}}\frac{275}{4}=\frac{25}{2}\times breadth\phantom{\rule{0ex}{0ex}}breadth=\frac{275}{4}\times \frac{2}{25}=\frac{11}{2}=5\frac{1}{2}m$

For remaining queries, we request you to post them in separate threads to have rapid assistance from our experts.

Regards!

**
**