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D e a r S t u d e n t M e a n o f 10 i n n i n g s = 54 T h e r e f o r e, 54 = \frac{x}{10} x = 540 w h e r e x i s t h e s u m o f s c o r e s o f 10 i n n i n g s L e t t h e n e w s c o r e = y N e w M e a n = 60 60 = \frac{x + y}{11} 60 = \frac{540 + y}{11} 60 \times 11 = 540 + y 660 = 540 + y y = 120 T h e s c o r e o f t h e 11^{t h} i n n i n g s = y = 120 R e g a r d s

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