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Given α, β  zeros of ax2 -5x +c α + β  = αβ  = 10Sum of zeroes= α+β = 10 = -coefficient of xcoefficient of x2    = -ba                  10   = -ba                 10 = -(-5)a                a = 510  = 12Product of zeroes  = αβ = 10 = constant termcoefficient of x2    = ca 10 = c1210 = 2cc = 5a = 12c = 5Regards

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