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Please Experts answer my question in detailed manner and please give step by step explaination

Only and only for EXPERTS
Only and only for EXPERTS

Not to unnecessarily comment on my post

Not to unnecessarily comment on my post

Dear Student,

As the wire is stretched double its length, its cross section area will become half[volume is constant and volume=length×area]

Given,R=30ΩR=ρLA=30ΩRnew=ρ(2L)A2=4ρLA=120ΩAs wire is bend to form equilateral triangle, resistance of each side=1203=40ΩWe know,Req=R1+R2  [In series]Req=R1×R2R1+R2 [In parallel]


Req=40+40=80Ω [Upper two arms in series]Req=80×4080+40=803Ω [Upper and lower arms in parallel]


Regards,

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