Please EXPERTS answer my question ... Share with your friends Share 0 Sejal Gupta answered this Dear Student,h2=-4cm(image is real)h1=1cmu(object distance)=-20cmwe know that,m=h2h1=-vu⇒-41=-v-20⇒v=-80cmNow, 1f=1v+1u1f=1-80+1-20f=-16cmThis is the focal length of the mirror.Now according to question,Height of image = 2 × height of objecti.e,hi=2ho-2hoh0=-vu⇒v=2uNow putting in formula we get,1f=1v+1u1-16=12u+1u⇒u=-24cmRegards 0 View Full Answer
