Please explain question Share with your friends Share 0 Ankita Agarwal answered this Dear Student, Since x313y is multiple of 55 so it should be divisible of 5 and 11.But it is a five digit number so x cannot be zero.Now checking for divisibility by 11 , Sum of digits at odd places-sum of digits at even places =0x+1+y=3+3x+y=5................1now divisibility by 5 , last digit should be 0 or 5 , soy = 0 or y = 5but when y = 5 then x will be zero and that is not possible.So x = 5, y=0now x2+y2+x=25+0+5=30 Regards. -1 View Full Answer
