please explain the line in ex 3 -  on comparing the indices of x in x2 and tr+1 , we obtain r=4.........

Dear Student!

Here is the answer to your query.


Suppose x2 occurs in the (r + 1)th term of the exposition



Comparing the indices or power of x in x2 and Tr + 1 we obtain


Thus  x2 occurs in (4 + 1)th term = 5th term

and its coefficient in the expansion of is given by



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 thank you

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r/2=2 How ?? cant understand

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