Please explain the steps.. Equivalent resistance of the network between X and Y, for R =100 Ω is (A) 373.5 Ω (B) 182.5 Ω (C) 212.5 Ω (D) 314.5 Ω Share with your friends Share 3 Decoder_2 answered this Dear student, The resistance R1 will be eliminated due to the Wheatstone bridge, Resistance of first network=2002=100ohmResistance of middle network,R=100+100=200ohm1R'=1200+1100R'=2003R''=2003+100=50031RNET=3500+1100RNET=62.5ohmResistance of last network,1r'=1200+1100r'=20031rnet=3200+1200rnet=50ohmNet resistance=100+62.5+50=212.5ohmRegards 0 View Full Answer Padmin Bhat answered this I hope it helps.When product of opp. Resistance is equal ,then zero deflection is shown the galvanometer ,there fore no current flows through the mid wire.Now calculate r eq 0