Please explain the steps..
Equivalent resistance of the network between X and Y, for R =100 Ω is

(A) 373.5 Ω      (B) 182.5 Ω       (C) 212.5 Ω             (D) 314.5 Ω

Dear student,
The resistance R1 will be eliminated due to the Wheatstone bridge,

Resistance of first network=2002=100ohmResistance of middle network,R=100+100=200ohm1R'=1200+1100R'=2003R''=2003+100=50031RNET=3500+1100RNET=62.5ohmResistance of last network,1r'=1200+1100r'=20031rnet=3200+1200rnet=50ohmNet resistance=100+62.5+50=212.5ohmRegards

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I hope it helps.When product of opp. Resistance is equal ,then zero deflection is shown the galvanometer ,there fore no current flows through the mid wire.Now calculate r eq

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