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Q. 
Two coins are tossed simultaneously 200 times and we get two heads: 58 times, one head: 83 times: 0 head: 59 times.
When two coins are tossed at random, what is the probability of getting (i) 2 heads, (ii) 1 head, (iii) 0 head?

A.
Total number of trials = 200
Number of times 2 heads are obtained = 58
Number of times one head is obtained  = 83
Number of times no head is obtained = 59

(i) Probability of getting 2 heads =  $\frac{\mathrm{Number} \mathrm{of} \mathrm{times} 2 \mathrm{heads} \mathrm{have} \mathrm{been} \mathrm{obtained}}{\mathrm{Total} \mathrm{number} \mathrm{of} \mathrm{trials} }$ = $\frac{58}{200}=\frac{29}{100}$


(ii) Probability of getting 1 head = $\frac{\mathrm{Number} \mathrm{of} \mathrm{times} 1 \mathrm{head} \mathrm{has} \mathrm{been} \mathrm{obtained}}{\mathrm{Total} \mathrm{number} \mathrm{of} \mathrm{trials} }$ = $\frac{83}{200}$


(iii) Probability of getting 0 head =  $\frac{\mathrm{Number} \mathrm{of} \mathrm{times} \mathrm{head} \mathrm{has} \mathrm{not} \mathrm{been} \mathrm{obtained}}{\mathrm{Total} \mathrm{number} \mathrm{of} \mathrm{trials} }$ = $\frac{59}{200}$

Regards