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Assuming the tangents are drawn from Point P  to circle  at points A and BWe know that tangents drawn from an external point to circle are equal in lengthPA=PBPAB=PBA   angles opposite to equal sides are equal in length Given: APB=60°Consider APB, by angle sum property of PAB+PBA+APB=180°PAB+PAB+60°=180°2PAB=120°PAB=60°Hence APB is equilateral  as each  angle is e 60° each All sides are equal in length.AP=PB=ABAB=5 cm given AP=5 cm

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