Please help me with the following question.
Dear student,
(a) Data is entered upto 3 decimal place. hence least count is 0.01 mm
(b) Least count is 0.01 mm so the instrument is screw gauge.
(c) error is ±0.01 mm
(d) percentage error = (0.01/2.70) × 100 = 0.37%
Regards
(a) Data is entered upto 3 decimal place. hence least count is 0.01 mm
(b) Least count is 0.01 mm so the instrument is screw gauge.
(c) error is ±0.01 mm
(d) percentage error = (0.01/2.70) × 100 = 0.37%
Regards